When dealing with skew-symmetric matrices, remember that the elements satisfy the property \( a_{ij} = -a_{ji} \), which means each element is the negative of its corresponding off-diagonal element. Diagonal elements are always zero. Use this property to solve for unknowns and verify the consistency of the matrix. In such problems, carefully apply the skew-symmetric condition to each pair of elements and solve the resulting equations.
A matrix is skew-symmetric if \( a_{ij} = -a_{ji} \) and the diagonal elements are zero.
From \( a_{13} = 3x \) and \( a_{31} = -6 \):
\[ 3x = -(-6) \implies 3x = 6 \implies x = 2. \]
From \( a_{23} = -5 \) and \( a_{32} = 5 \):
\[ y = -y \implies y = 0. \]
Substitute \( x = 2 \) and \( y = 0 \) into \( 5x - y \):
\[ 5x - y = 5(2) - 0 = 10. \]
A matrix is skew-symmetric if \( a_{ij} = -a_{ji} \) and the diagonal elements are zero.
Step 1: Given \( a_{13} = 3x \) and \( a_{31} = -6 \):
Since the matrix is skew-symmetric, \( a_{13} = -a_{31} \). Substituting the given values: \[ 3x = -(-6) \implies 3x = 6 \implies x = 2. \] Therefore, \( x = 2 \).Step 2: Given \( a_{23} = -5 \) and \( a_{32} = 5 \):
Similarly, for a skew-symmetric matrix, \( a_{23} = -a_{32} \). Substituting the given values: \[ y = -y \implies 2y = 0 \implies y = 0. \] Therefore, \( y = 0 \).Step 3: Substitute \( x = 2 \) and \( y = 0 \) into \( 5x - y \):
Now, substituting the values of \( x \) and \( y \) into the expression \( 5x - y \): \[ 5x - y = 5(2) - 0 = 10. \]Conclusion: The final value is \( 10 \).
List-I | List-II |
(A) Absolute maximum value | (I) 3 |
(B) Absolute minimum value | (II) 0 |
(C) Point of maxima | (III) -5 |
(D) Point of minima | (IV) 4 |
List-I(State) | List-II(National Park) |
(A) Madhya Pradesh | (I) Namdapha National Park |
(B) Arunachal Pradesh | (II) Guindy National Park |
(C) Meghalaya | (III) Nokrek National Park |
(D) Tamil Nadu | (IV) Kuno National Park |