Given the matrix \(A=\begin{bmatrix} 5 & 4a+6 \\ a+12 & a+3 \end{bmatrix}\). For the matrix to be symmetric, the elements across the main diagonal must be equal, i.e., the matrix \(A\) should satisfy the condition \(A = A^T\). This implies: \[A[i,j] = A[j,i]\] for all \(i\) and \(j\).
The matrix \(A\) is \(\begin{bmatrix} 5 & 4a+6 \\ a+12 & a+3 \end{bmatrix}\).
For symmetry, equate the off-diagonal elements: \[4a + 6 = a + 12\].
To find the value of \(a\), solve the equation:
\[4a + 6 = a + 12\]
Subtract \(a\) from both sides:
\[3a + 6 = 12\]
Subtract 6 from both sides:
\[3a = 6\]
Divide by 3:
\[a = 2\]
Thus, when \(a = 2\), the matrix \(A\) becomes \(\begin{bmatrix} 5 & 14 \\ 14 & 5 \end{bmatrix}\), which is symmetric. Therefore, the value of \(a\) is 2.