Given the matrix \(A=\begin{bmatrix} 5 & 4a+6 \\ a+12 & a+3 \end{bmatrix}\). For the matrix to be symmetric, the elements across the main diagonal must be equal, i.e., the matrix \(A\) should satisfy the condition \(A = A^T\). This implies: \[A[i,j] = A[j,i]\] for all \(i\) and \(j\).
The matrix \(A\) is \(\begin{bmatrix} 5 & 4a+6 \\ a+12 & a+3 \end{bmatrix}\).
For symmetry, equate the off-diagonal elements: \[4a + 6 = a + 12\].
To find the value of \(a\), solve the equation:
\[4a + 6 = a + 12\]
Subtract \(a\) from both sides:
\[3a + 6 = 12\]
Subtract 6 from both sides:
\[3a = 6\]
Divide by 3:
\[a = 2\]
Thus, when \(a = 2\), the matrix \(A\) becomes \(\begin{bmatrix} 5 & 14 \\ 14 & 5 \end{bmatrix}\), which is symmetric. Therefore, the value of \(a\) is 2.
Let $ A $ be a $ 3 \times 3 $ matrix such that $ | \text{adj} (\text{adj} A) | = 81.
$ If $ S = \left\{ n \in \mathbb{Z}: \left| \text{adj} (\text{adj} A) \right|^{\frac{(n - 1)^2}{2}} = |A|^{(3n^2 - 5n - 4)} \right\}, $ then the value of $ \sum_{n \in S} |A| (n^2 + n) $ is:
Three students, Neha, Rani, and Sam go to a market to purchase stationery items. Neha buys 4 pens, 3 notepads, and 2 erasers and pays ₹ 60. Rani buys 2 pens, 4 notepads, and 6 erasers for ₹ 90. Sam pays ₹ 70 for 6 pens, 2 notepads, and 3 erasers.
Based upon the above information, answer the following questions:
(i) Form the equations required to solve the problem of finding the price of each item, and express it in the matrix form \( A \mathbf{X} = B \).