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if the matrices matrix 1 0 0 0 matrix matrix 1 0 0
Question:
If the matrices
(
1
0
0
0
)
,
(
−
1
0
0
0
)
,
(
i
0
0
0
)
a
n
d
(
−
i
0
0
0
)
\left(\begin{matrix} 1 & 0 \\ 0 & 0 \end{matrix}\right),\left(\begin{matrix} -1 & 0 \\ 0 & 0 \end{matrix}\right),\left(\begin{matrix} i & 0 \\ 0 & 0 \end{matrix}\right) and \left(\begin{matrix} -i & 0 \\ 0 & 0 \end{matrix}\right)
(
1
0
0
0
)
,
(
−
1
0
0
0
)
,
(
i
0
0
0
)
an
d
(
−
i
0
0
0
)
form a group with respect to matrix multiplication, then which one of the following statements about the groups, thus formed is correct?
CUET (PG) - 2023
CUET (PG)
Updated On:
Mar 12, 2025
The group has no element of order 4.
The group has an element of order 3.
The group is non-abelian
(
−
1
0
0
0
)
\left(\begin{matrix} -1 & 0 \\ 0 & 0 \end{matrix}\right)
(
−
1
0
0
0
)
is its own inverse
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The Correct Option is
D
Solution and Explanation
The correct answer is(D):
(
−
1
0
0
0
)
\left(\begin{matrix} -1 & 0 \\ 0 & 0 \end{matrix}\right)
(
−
1
0
0
0
)
is its own inverse
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Top Questions on Matrices
Four friends Abhay, Bina, Chhaya, and Devesh were asked to simplify
4
A
B
+
3
(
A
B
+
B
A
)
−
4
B
A
4 AB + 3(AB + BA) - 4 BA
4
A
B
+
3
(
A
B
+
B
A
)
−
4
B
A
, where
A
A
A
and
B
B
B
are both matrices of order
2
×
2
2 \times 2
2
×
2
. It is known that
A
≠
B
A \neq B
A
=
B
and
A
−
1
≠
B
A^{-1} \neq B
A
−
1
=
B
. Their answers are given as:
CBSE CLASS XII - 2025
Mathematics
Matrices
View Solution
Given
A
=
[
−
4
4
4
−
7
1
3
5
−
3
−
1
]
,
B
=
[
1
−
1
1
1
−
2
−
2
2
1
3
]
A = \begin{bmatrix} -4 & 4 & 4 \\ -7 & 1 & 3 \\ 5 & -3 & -1 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & -1 & 1 \\ 1 & -2 & -2 \\ 2 & 1 & 3 \end{bmatrix}
A
=
−
4
−
7
5
4
1
−
3
4
3
−
1
,
B
=
1
1
2
−
1
−
2
1
1
−
2
3
find
A
B
AB
A
B
. Hence, solve the system of linear equations:
x
−
y
+
z
=
4
,
x - y + z = 4,
x
−
y
+
z
=
4
,
x
−
2
y
−
2
z
=
9
,
x - 2y - 2z = 9,
x
−
2
y
−
2
z
=
9
,
2
x
+
y
+
3
z
=
1.
2x + y + 3z = 1.
2
x
+
y
+
3
z
=
1.
CBSE CLASS XII - 2025
Mathematics
Matrices
View Solution
If
A
=
[
1
2
0
−
2
−
1
−
2
0
−
1
1
]
A = \begin{bmatrix} 1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1 \end{bmatrix}
A
=
1
−
2
0
2
−
1
−
1
0
−
2
1
then find
A
−
1
A^{-1}
A
−
1
. Hence, solve the system of linear equations:
x
−
2
y
=
10
,
x - 2y = 10,
x
−
2
y
=
10
,
2
x
−
y
−
z
=
8
,
2x - y - z = 8,
2
x
−
y
−
z
=
8
,
−
2
y
+
z
=
7.
-2y + z = 7.
−
2
y
+
z
=
7.
CBSE CLASS XII - 2025
Mathematics
Matrices
View Solution
Assertion (A):
A
=
diag
[
3
,
5
,
2
]
A = \text{diag} [3, 5, 2]
A
=
diag
[
3
,
5
,
2
]
is a scalar matrix of order
3
×
3
3 \times 3
3
×
3
.
Reason (R):
If a diagonal matrix has all non-zero elements equal, it is known as a scalar matrix.
CBSE CLASS XII - 2025
Mathematics
Matrices
View Solution
If
A
A
A
and
B
B
B
are square matrices of order
m
m
m
such that
A
2
−
B
2
=
(
A
−
B
)
(
A
+
B
)
A^2 - B^2 = (A - B)(A + B)
A
2
−
B
2
=
(
A
−
B
)
(
A
+
B
)
, then which of the following is always correct?
CBSE CLASS XII - 2025
Mathematics
Matrices
View Solution
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