Question:

If the mass of moon is $ \frac{\text{M}}{\text{81}}\text{,} $ where M is the mass of earth, find the distance of the point from the moon, where gravitational field due to earth and moon cancel each other. Given that distance between earth and moon is 60R, where R is the radius of earth.

Updated On: Sep 3, 2024
  • 6R
  • BR
  • 2R
  • 4R
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The Correct Option is A

Solution and Explanation

Key Idea: Where gravitational field due to earth and moon cancel each other, there the gravitational force is equal.
From Newtons law of gravitational the force of attraction between any two material particles is given by
$ F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} $
where $ {{m}_{1}},{{m}_{2}} $ are masses and $ r $ is the distance between the two.
Since gravitational fields cancel each other the force of attraction is same and opposite. i.e.,
$ {{F}_{1}}={{F}_{2}} $
$ \frac{G\left( \frac{M}{81} \right)m}{{{x}^{2}}}=\frac{GM\times m}{{{(60\,R-x)}^{2}}} $
$ \Rightarrow $ $ \frac{1}{81{{x}^{2}}}=\frac{1}{{{(60R-x)}^{2}}} $
Taking square root of the above expression, we have
$ \frac{1}{9x}=\frac{1}{60R-x} $
$ \Rightarrow $ $ 9x=60R-x $
$ \Rightarrow $ $ x=6R $
Hence, distance of that point from moon is 6R.
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Concepts Used:

Newtons Law of Gravitation

Gravitational Force

Gravitational force is a central force that depends only on the position of the test mass from the source mass and always acts along the line joining the centers of the two masses.

Newton’s Law of Gravitation:

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • Directly proportional to the product of their masses i.e. F ∝ (M1M2) . . . . (1)
  • Inversely proportional to the square of the distance between their center i.e. (F ∝ 1/r2) . . . . (2)

By combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2 [f(r)is a variable, Non-contact, and conservative force]