If the frequency of a wave is increased by 25%, then the change in its wavelength is (medium not changed):
Step 1: Understanding the Wave Relation The relationship between the speed \( v \), frequency \( f \), and wavelength \( \lambda \) of a wave is given by the equation: \[ v = f \lambda \] Since the medium is unchanged, the wave speed \( v \) remains constant.
Step 2: Finding the Change in Wavelength Rearranging the equation for wavelength: \[ \lambda = \frac{v}{f} \] If the frequency increases by 25\%, then the new frequency is: \[ f' = 1.25 f \] Since wave speed is constant, the new wavelength becomes: \[ \lambda' = \frac{v}{1.25 f} = \frac{\lambda}{1.25} \]
Step 3: Calculating Percentage Change in Wavelength The percentage change in wavelength is: \[ \left( \frac{\lambda' - \lambda}{\lambda} \right) \times 100 = \left( \frac{\frac{\lambda}{1.25} - \lambda}{\lambda} \right) \times 100 \] \[ = \left( \frac{\lambda - 1.25\lambda}{1.25\lambda} \right) \times 100 \] \[ = \left( \frac{1 - 1.25}{1.25} \right) \times 100 \] \[ = \left( \frac{-0.25}{1.25} \right) \times 100 \] \[ = -20\% \] Thus, the wavelength decreases by 20%.
A sub-atomic particle of mass \( 10^{-30} \) kg is moving with a velocity of \( 2.21 \times 10^6 \) m/s. Under the matter wave consideration, the particle will behave closely like (h = \( 6.63 \times 10^{-34} \) J.s)