Question:

If the expansion of \(\left(x^2 + \frac{2}{x} \right)^n\) has a term independent of \(x\), then \(n\) is

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Isobars have the same mass number but belong to different elements.
Updated On: Mar 30, 2025
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  • 18
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The Correct Option is B

Solution and Explanation


General term: \[ T_{r+1} = \binom{n}{r} (x^2)^{n-r} \left(\frac{2}{x}\right)^r = \binom{n}{r} 2^r x^{2(n - r) - r} = \binom{n}{r} 2^r x^{2n - 3r} \] For independence of \(x\): \[ 2n - 3r = 0 \Rightarrow r = \frac{2n}{3} \] r must be integer ⇒ \(n\) must be divisible by 3 ⇒ smallest integer satisfying this: \(n = 18\)
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