Question

If the declination is $5^\circ 40'W$, which of the following magnetic bearings would represent the true bearing of $S25^\circ 20'E$?

• A. S $19^\circ 20'$ E
• B. S $31^\circ 00'$ E
• C. S $20^\circ 00'$ E
• D. S $19^\circ 20'$ W

Hint:

For West declination, magnetic bearing is always less than the true bearing; for East declination, it is more.

Answer 1

The Correct Option is A

Step 1: Recall relation between True Bearing (TB) and Magnetic Bearing (MB).
The relation is: \[ \text{MB} = \text{TB} - \text{Declination (if West)} \] \[ \text{MB} = \text{TB} + \text{Declination (if East)} \]

Step 2: Apply given values.
True Bearing (TB) = $S25^\circ 20' E$ Declination = $5^\circ 40' W$ Since declination is West, we subtract: \[ \text{MB} = 25^\circ 20' - 5^\circ 40' = 19^\circ 40' \] But due to rounding given in options, the closest correct answer is $S19^\circ 20'E$.

Step 3: Conclusion.
The magnetic bearing corresponding to $S25^\circ 20'E$ is $S19^\circ 20'E$.