Question:

If the compound interest for 2 years at 10% per annum is Rs.1050, then the principal amount is

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For 2-year compound interest, use $(1 + R/100)^2 - 1$ shortcut.
Updated On: Feb 25, 2026
  • Rs.5000
  • Rs.5500
  • Rs.6000
  • Rs.6500
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The Correct Option is A

Solution and Explanation

Concept: Compound interest for 2 years: \[ CI = P \left[\left(1 + \frac{R}{100}\right)^2 - 1\right] \] Explanation: Rate $R = 10\%$ \[ CI = P[(1.1)^2 - 1] = P(1.21 - 1) = 0.21P \] Given: \[ 0.21P = 1050 \Rightarrow P = \frac{1050}{0.21} = 5000 \]
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