1. Let the breadth of the rectangle be \( x \) meters:
Since the length is 6 meters more than the breadth, the length is \( x + 6 \) meters.
2. Using the formula for the area of a rectangle:
The area is given by: \( \text{Area} = \text{Length} \times \text{Breadth} \).
We know the area is 112 m², so:
\( x(x + 6) = 112 \)
3. Simplifying the equation:
Expand the equation: \( x^2 + 6x = 112 \)
Rearrange it to form a quadratic equation:
\( x^2 + 6x - 112 = 0 \)
4. Solving the quadratic equation:
We can solve it using the quadratic formula:
\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Here, \( a = 1 \), \( b = 6 \), and \( c = -112 \).
Substitute these values into the quadratic formula:
\( x = \frac{-6 \pm \sqrt{6^2 - 4(1)(-112)}}{2(1)} \)
\( x = \frac{-6 \pm \sqrt{36 + 448}}{2} \)
\( x = \frac{-6 \pm \sqrt{484}}{2} \)
\( x = \frac{-6 \pm 22}{2} \)
Therefore, \( x = \frac{-6 + 22}{2} = \frac{16}{2} = 8 \) or \( x = \frac{-6 - 22}{2} = \frac{-28}{2} = -14 \).
Since the breadth cannot be negative, we have \( x = 8 \) meters.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$