Question:

If spheres of radius $'r'$ are arranged in ccp fashion (ABCABC.....), the vertical distance between any two consecutive A layers is

Updated On: Jul 6, 2022
  • $4 r \sqrt{\frac{2}{3}}$
  • $4 r \sqrt{\frac{3}{2}}$
  • 6r
  • $e \sqrt{6}$
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The Correct Option is A

Solution and Explanation

Distance between two consecutive A layers (d) $ = 2 \sqrt{\frac{2}{3}} a$ But $a = 2 r$ $\therefore \, d = 2 \sqrt{\frac{2}{3}} \times 2r = 4 r \sqrt{\frac{2}{3}}$
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Concepts Used:

Solid State

Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions. 

Solid State

Types of Solids:

Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;

  • Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
  • Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.