Question:

If some heat is given to a metal of mass 100 g, its temperature rises by 20 $^\circ$C. If the same heat is given to 20 g of water, the change in its temperature (in $^\circ$C) is (The ratio of specific heat capacities of metal and water is 1:10)

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Use the relation \(Q = m C \Delta T\) and equate heat supplied to both substances to find the unknown temperature change.
Updated On: Jun 4, 2025
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The Correct Option is B

Solution and Explanation

Given: Mass of metal, \(m_m = 100\, g\), temperature rise \(\Delta T_m = 20^\circ C\)
Mass of water, \(m_w = 20\, g\)
Ratio of specific heat capacities \(C_m : C_w = 1 : 10\)
Heat given \(Q\) is same for both: \[ Q = m_m C_m \Delta T_m = m_w C_w \Delta T_w \] \[ \Rightarrow 100 \times C_m \times 20 = 20 \times 10 C_m \times \Delta T_w \] Simplify: \[ 2000 C_m = 200 C_m \Delta T_w \Rightarrow \Delta T_w = \frac{2000}{200} = 10^\circ C \]
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