In the case of a solid in equilibrium with its vapor, there is a simple phase transition occurring between the solid and vapor phases. In this system, there is only one degree of freedom, which corresponds to the ability to vary either the temperature or the pressure independently, as the system remains in equilibrium at the phase boundary. This concept is described by the Gibbs phase rule, which for a two-phase system with two components is given by:
\[
F = C - P + 2
\]
Where \( F \) is the degrees of freedom, \( C \) is the number of components, and \( P \) is the number of phases. For solid tin in equilibrium with its vapor (2 phases), and 1 component (tin), the number of degrees of freedom is:
\[
F = 1 - 2 + 2 = 1
\]
Thus, the degree of freedom is 1. Therefore, the correct answer is 1.