Question:
If \( \sin \theta, \cos \theta, \tan \theta \) are in G.P., then \( \cos^2 \theta + \cos \theta + 3 \cos \theta - 1 \) is equal to:
If \( \sin \theta, \cos \theta, \tan \theta \) are in G.P., then \( \cos^2 \theta + \cos \theta + 3 \cos \theta - 1 \) is equal to:
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In G.P., the square of the middle term equals the product of the other two terms. Use this property to solve trigonometric equations.
Updated On: Jan 6, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Relationship between sine, cosine, and tangent.
Since \( \sin \theta, \cos \theta, \tan \theta \) are in geometric progression (G.P.), use the relationship between them to derive the value of the given expression.
Step 2: Conclusion. Thus, the value of the given expression is 0.
Step 2: Conclusion. Thus, the value of the given expression is 0.
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