The number of subsets of a set with 8 elements is \( 2^8 = 256 \). We are asked to find the number of subsets that contain at least 6 elements.
Step 1: Use the binomial coefficient to calculate the number of subsets with exactly 6, 7, and 8 elements: \( \binom{8}{6} + \binom{8}{7} + \binom{8}{8} = \frac{8 \times 7}{2 \times 1} + \frac{8}{1} + 1 = 28 + 8 + 1 = 37 \)
Step 2: The total number of subsets with at least 6 elements is 37.
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
Let $ S $ be the set of all seven-digit numbers that can be formed using the digits 0, 1 and 2. For example, 2210222 is in $ S $, but 0210222 is NOT in $ S $.
Then the number of elements $ x $ in $ S $ such that at least one of the digits 0 and 1 appears exactly twice in $ x $, is equal to __________.
The number of 6-letter words, with or without meaning, that can be formed using the letters of the word MATHS such that any letter that appears in the word must appear at least twice, is $ 4 \_\_\_\_\_$.