Step 1: Recall the properties of an equivalence relation.
An equivalence relation is reflexive, symmetric, and transitive.
Step 2: Since $R$ is transitive, we have:
\[
R \circ R \subseteq R
\]
Step 3: Because $R$ is also reflexive, every $(a,a) \in R$, which implies:
\[
R \subseteq R \circ R
\]
Step 4: Hence,
\[
R \circ R = R
\]
Step 5: Since $R$ itself is an equivalence relation, $R \circ R$ is also an equivalence relation.