Step 1: Analyze the given logical statements.
Statement 1: \( p \land q = F \) implies that at least one of \( p \) or \( q \) is False.
Statement 2: \( p \rightarrow q = F \) implies that \( p \) is True and \( q \) is False.
Step 2: From Statement 2, since \( p \rightarrow q \) is False, we have: \[ p = T \quad \text{and} \quad q = F \]
Conclusion: The truth values of \( p \) and \( q \) are \( T \) and \( F \), respectively.
An \( \alpha \) particle is scattered from an Au target at rest as shown in the figure. \( D_1 \) and \( D_2 \) are the detectors to detect the scattered \( \alpha \) particle at an angle \( \theta \) and along the beam direction, respectively, as shown. The signals from \( D_1 \) and \( D_2 \) are converted to logic signals and fed to logic gates. When a particle is detected, the signal is 1 and is 0 otherwise. Which one of the following circuits detects the particle scattered at the angle \( \theta \) only?
A logic gate circuit is shown in the figure below. The correct combination for the input \( (P, Q) \) for which the output \( T = 1 \) is:
For the circuit shown above, the equivalent gate is:
Which of the following compounds can exhibit geometrical isomerism, and why?
1) 2-butene
2) 1-butene ?
3) Pent-2-ene
4) But-2-yne