If one of the sides of a square is increased by 20% and the other side of decreased by 20% to get a rectangle, what percent of the area of the square will be the area of this rectangle?
Show Hint
When one side of a square increases and the other decreases, the area is impacted by the product of the increase and decrease percentages. The decrease will generally result in a smaller area than the original.
Let the side of the square be \( s \). The area of the square is:
\[
\text{Area of square} = s^2
\]
After increasing one side by 20% and decreasing the other side by 20%, the new dimensions of the rectangle are:
\[
\text{New side 1} = s \times 1.2 \quad \text{and} \quad \text{New side 2} = s \times 0.8
\]
Thus, the area of the rectangle is:
\[
\text{Area of rectangle} = s \times 1.2 \times s \times 0.8 = s^2 \times 0.96
\]
Therefore, the area of the rectangle is \( 96% \) of the area of the square.
Thus, the correct answer is \( 96% \).