Question:
If one of the diameters of the circle $x^2 + y^2 - 2x - 6y + 6 = 0$ is a chord to the circle with centre (2,1), then the radius of the circle is
If one of the diameters of the circle $x^2 + y^2 - 2x - 6y + 6 = 0$ is a chord to the circle with centre (2,1), then the radius of the circle is
Updated On: Jun 14, 2022
- $\sqrt3$
- $\sqrt2$
- 3
- 2
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The Correct Option is C
Solution and Explanation
Here, radius of sm aller circle, AC = $\sqrt{1 + 9- 6} = 2$
Clearly, from the figure the radius of bigger circle
$r^2 = 2^2 + [(2 - 1)^2 + (1 - 3)^2] $
$r^2=9 \Rightarrow r = 3 $
Clearly, from the figure the radius of bigger circle
$r^2 = 2^2 + [(2 - 1)^2 + (1 - 3)^2] $
$r^2=9 \Rightarrow r = 3 $
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