Question

If \( N \) is the total number of rulings on the grating, \( n \) is the order of the spectrum, and \( \lambda \) is the wavelength of light, then the resolving power of the grating is:

• A. \( N n \lambda \)
• B. \( N n \)
• C. \( \frac{N \lambda}{n} \)
• D. \( \frac{N}{n} \)

Hint:

The resolving power of a grating is given by \( R = N n \), where \( N \) is the number of rulings and \( n \) is the order.

Answer 1

The Correct Option is B

The resolving power of a grating is given by:
\[ R = \frac{\lambda}{\Delta \lambda} = N n \] where:
- \( N \) is the total number of slits,
- \( n \) is the order of diffraction.