Question:
If \(log2\) = 0.30103, find number of digits in 256
If \(log2\) = 0.30103, find number of digits in 256
Updated On: Dec 1, 2025
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The Correct Option is C
Solution and Explanation
The correct is option (C): given \(log2\)=0.30103
let x= 256
\(logx\)=\(log2^{56} \)
\(log(x)\)=\(56log(2)\)
\(log(x)\)= \(56 \times 0.30103\) = 16.85
The no. of digits in 256 = 17
let x= 256
\(logx\)=\(log2^{56} \)
\(log(x)\)=\(56log(2)\)
\(log(x)\)= \(56 \times 0.30103\) = 16.85
The no. of digits in 256 = 17
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