Question:
If \(log_4m+log_4n=log_2(m+n)\) where m and n are positive real numbers, then which of the following must be true?
If \(log_4m+log_4n=log_2(m+n)\) where m and n are positive real numbers, then which of the following must be true?
Updated On: Aug 9, 2024
- \(\frac{1}{m} +\frac{1}{n} =1\)
- \(m=n\)
- \(m^2+n^2=1\)
- \(\frac{1}{m} +\frac{1}{n} =2\)
- No values of m and n can satisfy the given equation
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The Correct Option is
Solution and Explanation
The correct answer is option (E):No values of m and n can satisfy the given equation
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