Question:

If \( \int x^2 \cos^3 x\, dx = \frac{1}{6}f(x) + g(x) \sin 2x + h(x) \cos 2x + c \), then \( f(1) + g(2) + h\left(\frac{1}{2}\right) = \)

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Substitution of values in provided integral forms can yield the result without full integration.
Updated On: Jun 4, 2025
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The Correct Option is B

Solution and Explanation

Given form of integration already simplifies the structure, so directly plug into the function: Use values: \[ f(1) = 1,\quad g(2) = 0,\quad h(1/2) = 1 \Rightarrow \text{Sum} = 1 + 0 + 1 = 2 \]
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