This is a substitution cipher problem. We need to find the rule that transforms 'Clever' into 'XOVEVI'.
Step 1: Analyze the relationship between the letters.
Let's write the letters of the alphabet and their reverse pairs:
A B C D E F G H I J K L M
Z Y X W V U T S R Q P O N
Now let's map the original word to the coded word:
    
 C \(\rightarrow\) X (C is the 3rd letter from the start, X is the 3rd letter from the end)
    
 L \(\rightarrow\) O (L is the 12th from the start, O is the 12th from the end)
    
 E \(\rightarrow\) V (E is the 5th from the start, V is the 5th from the end)
    
 V \(\rightarrow\) E 
    
 E \(\rightarrow\) V
    
 R \(\rightarrow\) I (R is the 18th from the start, I is the 18th from the end)
The rule is: Each letter is replaced by its opposite letter in the alphabet.
Step 2: Apply the rule to the word 'Smart'.
We will find the opposite letter for each letter in 'Smart'.
    
 S \(\rightarrow\) The opposite of S is H.
    
 M \(\rightarrow\) The opposite of M is N.
    
 A \(\rightarrow\) The opposite of A is Z.
    
 R \(\rightarrow\) The opposite of R is I.
    
 T \(\rightarrow\) The opposite of T is G.
Step 3: Form the final coded word.
Combining the opposite letters, we get HNZIG.