Question

If each resistance in the given figure is 9 $\Omega$, then the reading of the ammeter (A) is

• A. 8 A
• B. 5 A
• C. 2 A
• D. 9 A

Hint:

For resistors in parallel, reciprocal of equivalent resistance is sum of reciprocals of individual resistances.

Answer 1

The Correct Option is B

The circuit shows 5 branches of 9 \(\Omega\) resistors in parallel (assuming each branch has one 9 \(\Omega\) resistor). Total equivalent resistance \(R_{eq}\) is: \[ \frac{1}{R_{eq}} = \sum \frac{1}{R_i} = \frac{5}{9} \Rightarrow R_{eq} = \frac{9}{5} = 1.8\, \Omega \] Given voltage \(V = 9 V\), total current: \[ I = \frac{V}{R_{eq}} = \frac{9}{1.8} = 5\, A \] Therefore, ammeter reads 5 A.