Given: Two fair sixβfaced dice are thrown. Let the sum of numbers be \(X\). We want: \[ P(7 < X < 10) \] So the possible integer values of \(X\) are: \[ X = 8, 9 \] Total possible outcomes: Each die has 6 faces β total = \(6 \times 6 = 36\).
Favourable outcomes:
\[ (2,6), (3,5), (4,4), (5,3), (6,2) \] Total = **5 outcomes**
\[ (3,6), (4,5), (5,4), (6,3) \] Total = **4 outcomes**
Probability: \[ P(7 < X < 10) = \frac{9}{36} = \frac{1}{4} = 0.25 \]
The sum of the payoffs to the players in the Nash equilibrium of the following simultaneous game is ............
| Player Y | ||
|---|---|---|
| C | NC | |
| Player X | X: 50, Y: 50 | X: 40, Y: 30 |
| X: 30, Y: 40 | X: 20, Y: 20 | |