Question

Two dice are thrown together. The probability of getting a sum more than 8 is

• A. \( \frac{7}{36} \)
• B. \( \frac{5}{12} \)
• C. \( \frac{5}{18} \)
• D. \( \frac{7}{18} \)

Hint:

To find the probability of a specific event, count the favorable outcomes and divide by the total number of possible outcomes.

Answer 1

The Correct Option is C

Step 1: Total possible outcomes.
When two dice are thrown, the total number of outcomes is \( 6 \times 6 = 36 \).
Step 2: Favorable outcomes.
The sums greater than 8 are: 9, 10, 11, and 12. We list the pairs that produce these sums: - Sum 9: (3, 6), (4, 5), (5, 4), (6, 3) — 4 outcomes - Sum 10: (4, 6), (5, 5), (6, 4) — 3 outcomes - Sum 11: (5, 6), (6, 5) — 2 outcomes - Sum 12: (6, 6) — 1 outcome Thus, the total number of favorable outcomes is \( 4 + 3 + 2 + 1 = 10 \).
Step 3: Probability calculation.
The probability of getting a sum greater than 8 is: \[ P = \frac{10}{36} = \frac{5}{18} \]
Step 4: Conclusion.
Therefore, the correct answer is (3) \( \frac{5}{18} \).