Question:
If \(\begin{bmatrix} a+2&3b+2c\\c+3&7d+6 \end{bmatrix}=\begin{bmatrix} 2&-3\\3c&-8 \end{bmatrix}\), then the values of a,b,c and d are.
If \(\begin{bmatrix} a+2&3b+2c\\c+3&7d+6 \end{bmatrix}=\begin{bmatrix} 2&-3\\3c&-8 \end{bmatrix}\), then the values of a,b,c and d are.
Updated On: Jun 14, 2024
- a=-2, b=0, c=-3, d=-2
- a=0, b=-2, c=-2, d=\(\frac{3}{2}\)
- a=-1, b=-3, c=\(\frac{-3}{2}\), d=2
- a=0, b=-2, c=\(\frac{3}{2}\), d=-2
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The Correct Option is D
Solution and Explanation
The correct option is (D): a=0, b=-2, c=\(\frac{3}{2}\), d=-2
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