Question:

If \[ \begin{bmatrix} 1 & 3 \\ 4 & 5 \end{bmatrix} \begin{bmatrix} x \\ 2 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix}, \] then the value of \( x \) is:

Updated On: Jun 2, 2025
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The Correct Option is A

Approach Solution - 1

To solve the problem, we need to determine the value of \( x \) in the matrix equation: \[\begin{bmatrix} 1 & 3 \\ 4 & 5 \end{bmatrix} \begin{bmatrix} x \\ 2 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix}\]
First, carry out the matrix multiplication on the left side:
\[\begin{bmatrix} 1 & 3 \\ 4 & 5 \end{bmatrix} \begin{bmatrix} x \\ 2 \end{bmatrix} = \begin{bmatrix} (1 \cdot x) + (3 \cdot 2) \\ (4 \cdot x) + (5 \cdot 2) \end{bmatrix} = \begin{bmatrix} x + 6 \\ 4x + 10 \end{bmatrix}\]
This results in the equation:
\[\begin{bmatrix} x + 6 \\ 4x + 10 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix}\]
From this, we have two separate equations:
1. \(x + 6 = 5\)
2. \(4x + 10 = 6\)
Solve the first equation:
\[x + 6 = 5 \]
Subtract 6 from both sides:
\[x = 5 - 6\]
\[x = -1\]
Check the solution with the second equation:
\[4x + 10 = 6\]
Substitute \(x = -1\):
\[4(-1) + 10 = 6\]
\[-4 + 10 = 6\]
\[6 = 6\]
The solution is consistent with both equations. Therefore, the value of \(x\) is \(-1\), which is the correct answer.
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Approach Solution -2

To find the value of \( x \) in the given matrix equation, we start by considering the matrices and their multiplication.
The equation is:
\[ \begin{bmatrix} 1 & 3 \\ 4 & 5 \end{bmatrix} \begin{bmatrix} x \\ 2 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix} \]

Perform matrix multiplication on the left-hand side:
\[ \begin{bmatrix} 1 \times x + 3 \times 2 \\ 4 \times x + 5 \times 2 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix} \]

This results in the system of equations:
\( 1x + 6 = 5 \) (Equation 1)
\( 4x + 10 = 6 \) (Equation 2)

Solve Equation 1 for \( x \):
\( x + 6 = 5 \)
\( x = 5 - 6 \)
\( x = -1 \)

Verify using Equation 2:
\( 4(-1) + 10 = 6 \)
\( -4 + 10 = 6 \)
\( 6 = 6 \), which is true.

Thus, the value of \( x \) is -1.
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