To solve the problem, we need to determine the value of \( x \) in the matrix equation: \[\begin{bmatrix} 1 & 3 \\ 4 & 5 \end{bmatrix} \begin{bmatrix} x \\ 2 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix}\]
First, carry out the matrix multiplication on the left side:
\[\begin{bmatrix} 1 & 3 \\ 4 & 5 \end{bmatrix} \begin{bmatrix} x \\ 2 \end{bmatrix} = \begin{bmatrix} (1 \cdot x) + (3 \cdot 2) \\ (4 \cdot x) + (5 \cdot 2) \end{bmatrix} = \begin{bmatrix} x + 6 \\ 4x + 10 \end{bmatrix}\]
This results in the equation:
\[\begin{bmatrix} x + 6 \\ 4x + 10 \end{bmatrix} = \begin{bmatrix} 5 \\ 6 \end{bmatrix}\]
From this, we have two separate equations:
1. \(x + 6 = 5\)
2. \(4x + 10 = 6\)
Solve the first equation:
\[x + 6 = 5 \]
Subtract 6 from both sides:
\[x = 5 - 6\]
\[x = -1\]
Check the solution with the second equation:
\[4x + 10 = 6\]
Substitute \(x = -1\):
\[4(-1) + 10 = 6\]
\[-4 + 10 = 6\]
\[6 = 6\]
The solution is consistent with both equations. Therefore, the value of \(x\) is \(-1\), which is the correct answer.