Question:

If bx=ayb^x=a^y then,

Updated On: Oct 15, 2024
  • logalogb=yx\frac{log a}{log b}=\frac{y}{x}
  • logbloga=yx\frac{log b}{log a}=\frac{y}{x}
  • logbloga=xy\frac{log b}{log a}=\frac{x}{y}
  • Can't be determined
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The Correct Option is B

Solution and Explanation

The correct option is (B): logbloga=yx\frac{log b}{log a}=\frac{y}{x}
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