Question:
If a2 + b2 = 14ab, then log (\(\frac{a+b}{4}\))=
If a2 + b2 = 14ab, then log (\(\frac{a+b}{4}\))=
Updated On: May 4, 2024
- \(\frac{1}{2}\)(log a+ log b)
- \(\frac{1}{2}\)log (a)+ log (b)
- \(\frac{1}{2}\)log \((\frac{a}{b})\)
- \(\frac{1}{3}\)log \((\frac{a}{b})\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{1}{2}\)(log a+ log b)
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