If a team of 4 persons is to be selected out of 4 married couples to play mixed doubles tennis game, then the number of ways of forming a team in which no married couple appears is
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In problems avoiding couples or pairs, choose the group and exclude their corresponding partners from the next step.
Each married couple contributes 1 man and 1 woman. So we have 4 men and 4 women. We need to form a team of 2 men and 2 women such that no married couple appears. Step 1: Choose 2 men from 4: \( \binom{4}{2} = 6 \) ways Step 2: For each chosen pair of men, exclude their wives and choose 2 women from the remaining 2: \( \binom{2}{2} = 1 \) way So total = \( 6 \times 1 = 6 \) But we can also choose 2 women first and exclude their husbands. So again we get 6 new combinations. However, these are not double counted since pairings are distinct. So total = \( 6 + 6 = 12 \)