Let the side length of the square iron sheet be \( s \).
When the sheet is rolled into a cylinder, the circumference of the base of the cylinder equals the side of the square:
\[ \text{Circumference} = s \]
The circumference of a cylinder is given by:
\[ 2\pi r = s \]
Solving for the diameter \( D \):
\[ D = 2r = \frac{s}{\pi} \]
The ratio between the diameter and the side of the square is:
\[ \frac{D}{s} = \frac{\frac{s}{\pi}}{s} = \frac{1}{\pi} \]
Thus, the correct answer is \( \frac{1}{\pi} \) (Option B).
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.