The volume of the original large sphere:
\[
V = \frac{4}{3} \pi R^3 = \frac{4}{3} \pi (20)^3 = \frac{4}{3} \pi \times 8000 = \frac{32000}{3} \pi
\]
Let the radius of each smaller sphere be $r$. Since the large sphere is divided into 8 equal smaller spheres, total volume is conserved:
\[
8 \times \frac{4}{3} \pi r^3 = \frac{32000}{3} \pi
\]
Divide both sides by $\frac{4}{3} \pi$:
\[
8 r^3 = 8000 \implies r^3 = 1000 \implies r = \sqrt[3]{1000} = 10 \text{ cm}
\]
Thus, each smaller sphere has radius 10 cm.