Given a relation R on the set {1, 2, 3} defined by R = {(1, 1)}, we need to determine the properties of R.
Reflexive: A relation R is reflexive if for all a in the set, (a, a) belongs to R. In this case, the set is {1, 2, 3}. For R to be reflexive, (1, 1), (2, 2), and (3, 3) must be in R. However, R = {(1, 1)} does not contain (2, 2) and (3, 3), so R is not reflexive.
Symmetric: A relation R is symmetric if for every (a, b) in R, (b, a) is also in R. In this case, R = {(1, 1)}. Since (1, 1) is in R, and (1, 1) is equal to (1, 1), R is symmetric.
Transitive: A relation R is transitive if for every (a, b) and (b, c) in R, (a, c) is also in R. In this case, R = {(1, 1)}. If (1, 1) and (1, 1) are in R, then (1, 1) must be in R, which it is. Thus, R is transitive.
Since R is symmetric and transitive, but not reflexive, the correct option is (C) Symmetric and transitive.
The given relation \( R = \{(1, 1)\} \) is on the set \( \{1, 2, 3\} \).
1. Reflexive: A relation \( R \) is reflexive if for every element \( x \) in the set, \( (x, x) \) is in \( R \). - Here, the set is \( \{1, 2, 3\} \). For the relation to be reflexive, we need \( (1, 1) \), \( (2, 2) \), and \( (3, 3) \) to be in \( R \). - Since \( (2, 2) \) and \( (3, 3) \) are not in \( R \), the relation is not reflexive.
2. Symmetric: A relation \( R \) is symmetric if whenever \( (x, y) \) is in \( R \), \( (y, x) \) is also in \( R \). - The only pair in \( R \) is \( (1, 1) \), and its reverse, \( (1, 1) \), is also in \( R \). - Thus, the relation is symmetric.
3. Transitive: A relation \( R \) is transitive if whenever \( (x, y) \) and \( (y, z) \) are in \( R \), \( (x, z) \) must also be in \( R \). - The only pair in \( R \) is \( (1, 1) \), and since it is a self-loop, transitivity holds trivially.
- Therefore, the relation is transitive.
The relation \( R = \{(1, 1)\} \) is symmetric and transitive, but not reflexive.
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