Question

If a processor clock is rated as 2500 million cycles per second, then its clock period is

• A. \( 2.50 \times 10^{-10} \) sec
• B. \( 4.0 \times 10^{-10} \) sec
• C. \( 1.0 \times 10^{-10} \) sec
• D. \( 5.0 \times 10^{-10} \) sec

Hint:

To calculate the clock period, simply take the reciprocal of the clock frequency in Hz or cycles per second.

Answer 1

The Correct Option is B

The clock period \( T \) is the reciprocal of the clock frequency. Given the frequency is 2500 million cycles per second (2500 MHz), we can calculate the period as follows: \[ T = \frac{1}{\text{Frequency}} = \frac{1}{2500 \times 10^6} = 4.0 \times 10^{-10} \, \text{sec} \] Thus, the clock period is \( \boxed{4.0 \times 10^{-10}} \) sec.