Question:
A packet with the destination IP address 145.36.109.70 arrives at a router whose routing table is shown. Which interface will the packet be forwarded to?
A packet with the destination IP address 145.36.109.70 arrives at a router whose routing table is shown. Which interface will the packet be forwarded to?
Show Hint
When checking a destination IP address against a routing table, compare it with each subnet using the subnet mask and find the longest matching prefix.
Updated On: Jan 30, 2026
- E1
- E2
- E3
- E5
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
We are given the destination IP address \( 145.36.109.70 \), and we need to find which interface the packet will be forwarded to based on the routing table.
1. Convert the IP address to binary form:
The given IP address is \( 145.36.109.70 \), and in binary form it is: \[ 145 = 10010001, \quad 36 = 00100100, \quad 109 = 01101101, \quad 70 = 01000110 \] So, the binary form of \( 145.36.109.70 \) is: \[ 10010001.00100100.01101101.01000110 \]
2. Check against the routing table:
For Subnet
The subnet address
The given IP address
3. Conclusion:
Since the IP address \( 145.36.109.70 \) falls under the subnet
Thus, the correct answer is \( \boxed{A} \).
1. Convert the IP address to binary form:
The given IP address is \( 145.36.109.70 \), and in binary form it is: \[ 145 = 10010001, \quad 36 = 00100100, \quad 109 = 01101101, \quad 70 = 01000110 \] So, the binary form of \( 145.36.109.70 \) is: \[ 10010001.00100100.01101101.01000110 \]
2. Check against the routing table:
For Subnet
145.36.0.0/16:
The subnet address
145.36.0.0 with the subnet mask /16 covers addresses from 145.36.0.0 to 145.36.255.255.
The given IP address
145.36.109.70 falls within this range. Therefore, it matches this subnet.
3. Conclusion:
Since the IP address \( 145.36.109.70 \) falls under the subnet
145.36.0.0/16, it will be forwarded to Interface E1.
Thus, the correct answer is \( \boxed{A} \).
Was this answer helpful?
0
0
Top Questions on Computer Architecture
- A processor has 64 general-purpose registers and 50 distinct instruction types. An instruction is encoded in 32-bits. What is the maximum number of bits that can be used to store the immediate operand for the given instruction?
- GATE CS - 2025
- Computer Science and IT Engineering
- Computer Architecture
- Given Data:
- Two processors: \( M_1 \) and \( M_2 \)
- Four processes: \( P_1, P_2, P_3, P_4 \)
- CPU bursts: \( P_1 = 20 \), \( P_2 = 16 \), \( P_3 = 25 \), \( P_4 = 10 \)
- Priority order for \( M_1 \): \( P_1 > P_3 > P_2 > P_4 \)
- Priority order for \( M_2 \): \( P_2 > P_3 > P_4 > P_1 \)
- Scheduling: Non-preemptive priority scheduling
Step 1: Assigning Processes to Processors
At \( t = 0 \), both processors are free. The highest-priority process for each processor is scheduled:
- \( M_1 \) gets \( P_1 \) (highest priority on \( M_1 \), burst = 20 ms).
- \( M_2 \) gets \( P_2 \) (highest priority on \( M_2 \), burst = 16 ms).
Step 2: Scheduling Remaining Processes
- \( P_2 \) finishes at \( t = 16 \), so \( M_2 \) picks the next highest-priority process, \( P_3 \) (burst = 25 ms).
- \( P_1 \) finishes at \( t = 20 \), so \( M_1 \) picks \( P_4 \) (burst = 10 ms).
- \( P_4 \) finishes at \( t = 30 \), and \( P_3 \) finishes at \( t = 41 \).
Step 3: Calculate Waiting Times
- \( P_1 \) starts at 0, so waiting time = \( 0 \) ms.
- \( P_2 \) starts at 0, so waiting time = \( 0 \) ms.
- \( P_3 \) starts at 16, so waiting time = \( 16 \) ms.
- \( P_4 \) starts at 20, so waiting time = \( 20 \) ms.
Step 4: Compute Average Waiting Time
\[ \text{Average waiting time} = \frac{(0 + 0 + 16 + 20)}{4} = \frac{36}{4} = 9 \text{ ms}. \]
Final Answer: The average waiting time of the processes is \( 9 \) milliseconds.- GATE CS - 2025
- Computer Science and IT Engineering
- Computer Architecture
- Which of the following instruction format is used by stack-organised computer?
- CUET (PG) - 2025
- Data Science
- Computer Architecture
- Which of the following statements are true?
A. Address bus connects CPU to memory modules for data access.
B. System bus connects CPU to I/O devices, cache etc.
C. System bus is usually classified as data bus, address bus and control bus.
D. The width of data bus has no connection with the amount of the data that can be transferred simultaneously.- CUET (PG) - 2025
- Atmospheric Science
- Computer Architecture
- Which type of memory is used to store the BIOS (BASIC INPUT OUTPUT SYSTEM) in a computer?
- CUET (PG) - 2025
- Atmospheric Science
- Computer Architecture
View More Questions
Questions Asked in GATE CS exam
In a 4-bit ripple counter, if the period of the waveform at the last flip-flop is 64 microseconds, then the frequency of the ripple counter in kHz is ______________. {(Answer in integer)}
- GATE CS - 2025
- Flip-Flop
Consider the following C code segment:
int x = 126, y = 105; do { if (x > y) x = x - y; else y = y - x; } while (x != y); printf("%d", x);The output of the given C code segment is ____________. (Answer in integer)
- GATE CS - 2025
- Programming in C
The following two signed 2’s complement numbers (multiplicand \( M \) and multiplier \( Q \)) are being multiplied using Booth’s algorithm:
Multiplicand (\( M \)) Multiplier (\( Q \)) 1100 1101 1110 1101 1010 0100 1010 1010 The total number of addition and subtraction operations to be performed is __________. (Answer in integer)
- GATE CS - 2025
- Complementation
The maximum value of \(x\) such that the edge between the nodes B and C is included in every minimum spanning tree of the given graph is __________ (answer in integer).
- GATE CS - 2025
- Programming and Data Structures
Consider the following C program
The value printed by the given C program is __________ (Answer in integer).- GATE CS - 2025
- Programming in C
View More Questions