Question

If a particle of mass 'm' covers half of the horizontal circle with constant speed 'v', then the change in its kinetic energy is

• A. $mv^2$
• B. Zero (శూన్యం)
• C. $2mv^2$
• D. $\dfrac{1}{2}mv^2$

Hint:

Kinetic energy is a scalar and depends only on speed, not on the direction of motion.

Answer 1

The Correct Option is B

Kinetic energy depends on the magnitude of velocity: $KE = \frac{1}{2}mv^2$
Since speed remains constant throughout the motion along the circle, the kinetic energy also remains constant.
So the change in kinetic energy is zero.