Question:

If a normal chord at a point "t" on the parabola $y^2 = 4ax$ subtends a right angle at the vertex, then t =

Updated On: Jul 5, 2022
  • 1
  • $\sqrt{2}$
  • 2
  • $\sqrt{3}$
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The Correct Option is B

Solution and Explanation

Normal chord at a point $'t'$ on the parabola $y^2 = 4 \,ax$ subtends a right angle at the vertex. $\Rightarrow t^2 = 2$ $\Rightarrow t = \sqrt 2 $
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