Question:

If a linear antenna radiates a power \(P\) at a wavelength \(\lambda\), then the power radiated by the same antenna at a wavelength of \(\frac{\lambda}{\sqrt{3}}\) is:

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For antennas, power radiated varies inversely with the square of the wavelength. Reducing the wavelength increases the power radiated accordingly.
Updated On: Jun 2, 2025
  • \(P\)
  • \(\sqrt{3} P\)
  • \(\frac{P}{3}\)
  • \(3P\)
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The Correct Option is D

Solution and Explanation

Power radiated by a linear antenna is inversely proportional to the square of the wavelength, i.e., \[ P \propto \frac{1}{\lambda^2} \] Given the original power is \(P\) at wavelength \(\lambda\). At wavelength \(\frac{\lambda}{\sqrt{3}}\), the power radiated \(P'\) is: \[ P' = P \times \left(\frac{\lambda}{\frac{\lambda}{\sqrt{3}}}\right)^2 = P \times (\sqrt{3})^2 = 3P \] Thus, the power radiated at \(\frac{\lambda}{\sqrt{3}}\) is \(3P\).
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