Step 1: Let B = x.
Given that A exceeds B by 50%, we have:
\[
A = x + 50% \times x = 1.5x
\]
Step 2: B is less than C by 25%, so:
\[
B = C - 25% \times C = 0.75C
\]
Thus, \( C = \frac{B}{0.75} = \frac{x}{0.75} = \frac{4x}{3} \).
Step 3: Ratio of A to C.
We have \( A = 1.5x \) and \( C = \frac{4x}{3} \). Therefore, the ratio \( A : C \) is:
\[
A : C = \frac{1.5x}{\frac{4x}{3}} = \frac{1.5 \times 3}{4} = \frac{4.5}{4} = \frac{9}{8}
\]
Thus, the correct ratio is \( A : C = 9 : 8 \).
Final Answer: \[ \boxed{9:8} \]
A weight of $500\,$N is held on a smooth plane inclined at $30^\circ$ to the horizontal by a force $P$ acting at $30^\circ$ to the inclined plane as shown. Then the value of force $P$ is:
A steel wire of $20$ mm diameter is bent into a circular shape of $10$ m radius. If modulus of elasticity of wire is $2\times10^{5}\ \text{N/mm}^2$, then the maximum bending stress induced in wire is: