In this case, we are considering the coordination complex formation involving the Ni²⁺ ion and ethane-1,2-diamine (en), which is a bidentate ligand. The Ni²⁺ ion, initially present in the form of [Ni(H₂O)₆]²⁺, forms different coordination complexes as more en ligands are added.
[Ni(H₂O)₄en]²⁺: When one en ligand is added in a 1:1 ratio with Ni²⁺, this forms the complex [Ni(H₂O)₄en]²⁺. This complex absorbs light at a wavelength of 600 nm and appears pale blue in color.
[Ni(H₂O)₂(en)₂]²⁺: When en is added in a 2:1 ratio with Ni²⁺, a second en ligand coordinates with the Ni²⁺ ion, forming [Ni(H₂O)₂(en)₂]²⁺. This complex absorbs light at a wavelength of approximately 600 nm as well, and it appears blue/purple in color.
[Ni(en)₃]²⁺: When en is added in a 3:1 ratio with Ni²⁺, the Ni²⁺ ion forms a complex with three en ligands, resulting in [Ni(en)₃]²⁺. This complex absorbs light at a wavelength of 535 nm and appears violet in color.
For complex I ([Ni(H₂O)₄en]²⁺), the absorbed wavelength is 600 nm.
For complex III ([Ni(en)₃]²⁺), the absorbed wavelength is 535 nm.
The wavelengths of light absorbed for complexes I and III are:
600 nm for [Ni(H₂O)₄en]²⁺ (pale blue).
535 nm for [Ni(en)₃]²⁺ (violet).
Thus, the answer is 600 nm and 535 nm.
In this case, when ethane-1,2-diamine (en) is progressively added to the nickel complex \([Ni(H_2O)_6]^{2+}\), different coordination entities are formed based on the molar ratio of en to Ni:
I. [Ni(H2O)4en]2+(aq) (pale blue):
This complex is formed when the molar ratio of en to Ni is 1:1. The color is pale blue. This complex typically absorbs light at a wavelength of 600 nm.
III. [Ni(en)3]2+(aq) (violet):
This complex is formed when the molar ratio of en to Ni is 3:1. It is violet in color, and its absorption wavelength is typically at 535 nm.
Therefore, the correct wavelengths of light absorbed in case of I and III are 600 nm and 535 nm respectively.
Correct Option: (D) 600 nm and 535 nm
In the given graph, \( E_a \) for the reverse reaction will be