Question:

If a Carnot engine working between the temperatures \(300 \, \text{K}\) and \(600 \, \text{K}\) has work output of \(800 \, \text{J}\) per cycle, then the heat supplied to the engine from source per cycle is

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Use Carnot efficiency formula \( \eta = 1 - \frac{T_C}{T_H} \) and relate work to heat using \( \eta = \frac{W}{Q_H} \).
Updated On: Jun 3, 2025
  • \(1800 \, \text{J}\)
  • \(1000 \, \text{J}\)
  • \(2000 \, \text{J}\)
  • \(1600 \, \text{J}\)
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The Correct Option is D

Solution and Explanation

Efficiency of Carnot engine: \[ \eta = 1 - \frac{T_C}{T_H} = 1 - \frac{300}{600} = 0.5 \] \[ \text{Efficiency} = \frac{W}{Q_H} \Rightarrow 0.5 = \frac{800}{Q_H} \Rightarrow Q_H = \frac{800}{0.5} = 1600 \, \text{J} \]
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