Step 1: Interpret the problem
The question seems incomplete; assume it asks for the average speed. Total distance $d$, 40% at speed $v_1$ (distance $0.4d$), remaining 60% at speed $v_2$ (distance $0.6d$).
Step 2: Compute the average speed
Time for first part: $t_1 = \frac{0.4d}{v_1}$. Time for second part: $t_2 = \frac{0.6d}{v_2}$. Total time: $t = t_1 + t_2 = \frac{0.4d}{v_1} + \frac{0.6d}{v_2}$. Average speed: $v_{\text{avg}} = \frac{\text{total distance}}{\text{total time}} = \frac{d}{\frac{0.4d}{v_1} + \frac{0.6d}{v_2}}} = \frac{1}{\frac{0.4}{v_1} + \frac{0.6}{v_2}}} = \frac{v_1 v_2}{0.4 v_2 + 0.6 v_1} = \frac{5 v_1 v_2}{2 v_1 + 3 v_2} = \frac{5 v_1 v_2}{3 v_1 + 2 v_2}$.
Step 3: Match with options
The average speed $\frac{5 v_1 v_2}{3 v_1 + 2 v_2}$ matches option (4).