Question:

If A and B are square matrices of order 3 such that \(|A| = -1\), \(|B| = 3\) then \(|3AB|\) is:

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For an \(n \times n\) matrix \(A\), \(|kA| = k^n |A|\), where \(k\) is a scalar.
Updated On: May 18, 2025
  • \(-9\)
  • \(-81\)
  • \(-27\)
  • \(81\)
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The Correct Option is B

Solution and Explanation

Given \(|A| = -1\) and \(|B| = 3\), both matrices are of order 3. Using properties of determinants: \[ |3AB| = |3I \cdot A \cdot B| = |3I| \cdot |A| \cdot |B| \] where \(3I\) is the scalar matrix \(3\) times the identity matrix of order 3. \[ |3I| = 3^3 = 27 \] Therefore, \[ |3AB| = 27 \times (-1) \times 3 = -81 \]
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