Given \(|A| = -1\) and \(|B| = 3\), both matrices are of order 3. Using properties of determinants:
\[
|3AB| = |3I \cdot A \cdot B| = |3I| \cdot |A| \cdot |B|
\]
where \(3I\) is the scalar matrix \(3\) times the identity matrix of order 3.
\[
|3I| = 3^3 = 27
\]
Therefore,
\[
|3AB| = 27 \times (-1) \times 3 = -81
\]