Properties of Skew-Symmetric Matrices:
For a skew-symmetric matrix \( M \), the following rules apply:
This rule can help you quickly evaluate the options in such questions.
Step 1: Understanding the Concept:
A matrix \( M \) is symmetric if \( M^T = M \).
A matrix \( M \) is skew-symmetric if \( M^T = -M \).
We are given that \( A \) and \( B \) are skew-symmetric, so \( A^T = -A \) and \( B^T = -B \). We need to check the properties of combinations of these matrices. A useful property is that for a skew-symmetric matrix \( M \), \( M^k \) is symmetric if \( k \) is even, and skew-symmetric if \( k \) is odd.
Step 2: Key Formula or Approach:
We will use the properties of matrix transposition and the fact that for skew-symmetric matrices, the power \( k \) determines the symmetry of the matrix.
Step 3: Detailed Explanation:
1. \( A^3 + B^5 \) is skew-symmetric:
Let \( P = A^3 + B^5 \). Let's find its transpose:
\[ P^T = (A^3 + B^5)^T = (A^3)^T + (B^5)^T = (A^T)^3 + (B^T)^5 \] Since \( A^T = -A \) and \( B^T = -B \): \[ P^T = (-A)^3 + (-B)^5 = -A^3 - B^5 = -(A^3 + B^5) = -P \] Since \( P^T = -P \), the matrix is skew-symmetric. This statement is true.
2. \( A^{19} \) is skew-symmetric:
Let \( Q = A^{19} \). The power 19 is odd:
\[ Q^T = (A^{19})^T = (A^T)^{19} = (-A)^{19} = -A^{19} = -Q \] The matrix is skew-symmetric. This statement is true.
3. \( B^{14} \) is symmetric:
Let \( R = B^{14} \). The power 14 is even:
\[ R^T = (B^{14})^T = (B^T)^{14} = (-B)^{14} = B^{14} = R \] The matrix is symmetric. This statement is true.
4. \( A^4 + B^5 \) is symmetric:
Let \( S = A^4 + B^5 \). Let's find its transpose:
\[ S^T = (A^4 + B^5)^T = (A^4)^T + (B^5)^T = (A^T)^4 + (B^T)^5 \] \[ S^T = (-A)^4 + (-B)^5 = A^4 - B^5 \] For \( S \) to be symmetric, \( S^T \) must be equal to \( S \): \[ A^4 - B^5 = A^4 + B^5 \] This implies \( -B^5 = B^5 \), or \( 2B^5 = 0 \), which means \( B^5 \) must be the zero matrix. This is not true for all skew-symmetric matrices \( B \). Therefore, \( S \) is not generally symmetric. This statement is NOT true.
Step 4: Final Answer:
The statement that is not true is \( A^4 + B^5 \) is symmetric.
Match List-I with List-II
List-I (Matrix) | List-II (Inverse of the Matrix) |
---|---|
(A) \(\begin{bmatrix} 1 & 7 \\ 4 & -2 \end{bmatrix}\) | (I) \(\begin{bmatrix} \tfrac{2}{15} & \tfrac{1}{10} \\[6pt] -\tfrac{1}{15} & \tfrac{1}{5} \end{bmatrix}\) |
(B) \(\begin{bmatrix} 6 & -3 \\ 2 & 4 \end{bmatrix}\) | (II) \(\begin{bmatrix} \tfrac{1}{5} & -\tfrac{2}{15} \\[6pt] -\tfrac{1}{10} & \tfrac{7}{30} \end{bmatrix}\) |
(C) \(\begin{bmatrix} 5 & 2 \\ -5 & 4 \end{bmatrix}\) | (III) \(\begin{bmatrix} \tfrac{1}{15} & \tfrac{7}{30} \\[6pt] \tfrac{2}{15} & -\tfrac{1}{30} \end{bmatrix}\) |
(D) \(\begin{bmatrix} 7 & 4 \\ 3 & 6 \end{bmatrix}\) | (IV) \(\begin{bmatrix} \tfrac{2}{15} & -\tfrac{1}{15} \\[6pt] \tfrac{1}{6} & \tfrac{1}{6} \end{bmatrix}\) |