To solve the problem \(\log_{a^{4}}65536=2\), we want to find the value of 'a'.
First, understand the logarithmic equation:
\(\log_{a^{4}}65536=2\) implies that \((a^{4})^{2} = 65536\).
This is because if \(\log_{b}c = d\), then \(b^{d} = c\).
Thus, we have:
\(a^{8} = 65536\).
Next, express 65536 as a power of 2:
\(65536 = 2^{16}\).
The equation becomes:
\(a^8 = 2^{16}\).
Equate the exponents:
This gives \(a = 2^{2}\) because \(a^{8} = 2^{16}\) implies \(a = 2^{16/8} = 2^{2}\).
Therefore, the value of 'a' is 4.
The correct answer is 4, as derived from the calculation.





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