Question:
If \(|\bar{a}|=\sqrt{14},|\bar{b}|=\sqrt{10},|\bar{a}-\bar{b}|=\sqrt{24}\ and\ \theta\) is angle between \(\bar{a}\ and\ \bar{b}\), then \(\cos\theta=\)
If \(|\bar{a}|=\sqrt{14},|\bar{b}|=\sqrt{10},|\bar{a}-\bar{b}|=\sqrt{24}\ and\ \theta\) is angle between \(\bar{a}\ and\ \bar{b}\), then \(\cos\theta=\)
Updated On: Jun 6, 2024
- \(\frac{\sqrt{35}}{70}\)
- \(\frac{\sqrt{6}}{12}\)
- \(\frac{\sqrt{15}}{60}\)
- \(\frac{\sqrt{210}}{35}\)
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