Let the work done by 1 man in 1 day be \( \frac{1}{5 \times 19} = \frac{1}{95} \), and the work done by 1 woman in 1 day be \( \frac{1}{9 \times 19} = \frac{1}{171} \).
Now, for 3 men and 6 women:
\[
\text{Work done by 3 men} = 3 \times \frac{1}{95} = \frac{3}{95}
\]
\[
\text{Work done by 6 women} = 6 \times \frac{1}{171} = \frac{6}{171}
\]
Thus, total work done per day is:
\[
\frac{3}{95} + \frac{6}{171} = \frac{9}{285} + \frac{6}{171} = \frac{15}{285} = \frac{1}{19}
\]
Thus, 3 men and 6 women can complete the work in 15 days.