Step 1: Apply the triangle inequality theorem.
The triangle inequality theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. For sides \( a \), \( b \), and \( c \), the following inequalities must hold:
\[
a + b>c, \quad a + c>b, \quad b + c>a.
\]
In our case, the known sides are 4 and 11. Let the third side be \( x \). The inequalities are:
\[
4 + 11>x \quad \text{or} \quad x<15,
\]
\[
4 + x>11 \quad \text{or} \quad x>7,
\]
\[
11 + x>4 \quad \text{which is always true since \( x>0 \)}.
\]
Thus, the third side \( x \) must satisfy:
\[
7<x<15.
\]
Step 2: Analyze the options.
- (I) \( x = 5 \): This does not satisfy \( x>7 \), so 5 cannot be the third side.
- (II) \( x = 13 \): This satisfies \( 7<x<15 \), so 13 can be the third side.
- (III) \( x = 15 \): This does not satisfy \( x<15 \), so 15 cannot be the third side.
Conclusion:
Thus, the possible third sides are 13, so the correct answer is (C) I and II only.