Reaction of dihydrogen with dioxygen can be written as:
\(2H_2(g) + O_2(g) → 2H_2O(g)\)
Now, two volumes of dihydrogen react with one volume of dihydrogen to produce two volumes of water vapour.
Hence, ten volumes of dihydrogen will react with five volumes of dioxygen to produce ten volumes of water vapour.
LIST I | LIST II |
---|---|
A. 88 g of CO2 | I. 2 mol |
B. 6.023 × 1023 molecules of H2O | II. 1 mol |
C. 96 g of O2 | III. 6.023 × 1023 molecules |
D. 1 mol of any gas | IV. 3 mol |